1903 Iowa gubernatorial election

1903 Iowa gubernatorial election

← 1901 November 3, 1903 1906 →
 
Nominee Albert B. Cummins J. B. Sullivan
Party Republican Democratic
Popular vote 238,804 159,725
Percentage 57.14% 38.22%

Governor before election

Albert B. Cummins
Republican

Elected Governor

Albert B. Cummins
Republican

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The 1903 Iowa gubernatorial election was held on November 3, 1903. Incumbent Republican Albert B. Cummins defeated Democratic nominee J. B. Sullivan with 57.14% of the vote.

General election

Candidates

Major party candidates

  • Albert B. Cummins, Republican
  • J. B. Sullivan, Democratic

Other candidates

  • John F. Hanson, Prohibition
  • John M. Work, Socialist
  • Luman Hamlin Weller, People's

Results

1903 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican Albert B. Cummins (incumbent) 238,804 57.14%
Democratic J. B. Sullivan 159,725 38.22%
Prohibition John F. Hanson 12,375 2.96%
Socialist John M. Work 6,421 1.54%
Populist Luman Hamlin Weller 594 0.14%
Majority 79,079
Turnout
Republican hold Swing

References

  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 3, 2020.